Examples of Z-line in the following topics:
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- A
sarcomere is defined as the segment between two neighbouring, parallel Z-lines.
- Actin myofilaments
attach directly to the Z-lines, whereas myosin myofilaments attach via titin
molecules.
- Surrounding the Z-line is the
I-band, the region where actin myofilaments are not superimposed by myosin
myofilaments.
- The I-band is spanned by the titin
molecule connecting the Z-line with a myosin filament.
- Titin molecules connect the
Z-line with the M-line and provide a scaffold for myosin myofilaments.
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- FtsZ has been named after "Filamenting temperature-sensitive mutant Z".
- This ring is called the Z-ring.
- The Z-ring forms from smaller subunits of FtsZ filaments.
- Lines of FtsZ would line up together parallel and pull on each other creating a "cord" of many strings that tightens itself.
- The Z-ring forms from smaller subunits of FtsZ filaments.
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- A line is described by a point on the line and its angle of inclination, or slope.
- Every line lies in a plane which is determined by both the direction and slope of the line.
- A line in three dimensional space is given by a point, $P_0 (x_o,y_o,z_o),oraplane,M$, and its direction.
- $x = x_0 + at \\
y=y_0 +bt \\
z = z_0 +ct$
- $z> \ = \ z_0 + ct>$
-
- The introduction of the variable z means that the graphed functions now represent planes, rather than lines.
- $\left\{\begin{matrix} 3x+2y-z=6\\ -2x+2y+z=3\\ x+y+z=4\\ \end{matrix}\right.$
Since the coefficient of z is already 1 in the first equation, solve for z to get
- $z=3x+2y-6$.
- Working up again, plug y=2 and x=1 into the first substituted equation, $z=3x+2y-6,whichsimplifiestoz=1$.
- Now subtract two times the first equation from the third equation to get $2x+2y+z-2(x+y+z)=3-2(2),whichsimplifiestoz=1$.
-
- The tangent line (or simply the tangent) to a plane curve at a given point is the straight line that "just touches" the curve at that point.
- For a surface given by a differentiable multivariable function $z=f(x,y),theequationofthetangentplaneat(x_0,y_0,z_0)$ is given as:
- where $(x_0,y_0,z_0)$ is a point on the surface.
- Note the similarity of the equations for tangent line and tangent plane.
- The approximation works well as long as the point $(x,y,z) $ under consideration is close enough to $(x_0,y_0,z_0)$, where the tangent plane touches the surface.
-
- r is how far the point is from the origin, which is usually denoted $r=\sqrt{a^2+b^2}=\abs{z}.Theotherparameteristheangle\phi$ which the line from the origin to the point makes with the horizontal, measured in radians.
- It turns out, due to a theorem of the great mathematician Euler that we can write $zasthecomplexexpressionz=re^{i\phi}$.
- So if $z=re^{i\phi}$ and $w=se^{i\theta}$ are complex numbers, then the product of $z$ and $w$ is $zw=rse^{i(\phi+\theta)}$, which comes from simply multiplying as usual for exponential functions.
- From this we can see that the product of $z$ and $w$ is the complex numbers whose distance from the origin is the product of the distances from the origin of $z$ and $w,andwhoseanglewiththehorizontalisthesumoftheanglesofz$ and $w$ with the origin.
- For example, consider the complex number $z=\sqrt2e^{i\pi/4}=1+i$ and $w=\sqrt2e^{3i\pi/4} = -1+i$.
-
- The symbol for the complex conjugate of $z$ is $\overline{z}$.
- The number a2+b2 is the square of the length of the line segment from the origin to the number a+bi.
- The symbol for the modulus of $z$ is $\abs{z}$.
- Thus we can write $z\overline{z} = (a+bi)(a-bi)=a^2+b^2=\abs{z}^2,orinotherwords,\abs{z}=\sqrt{z\overline{z}}.$
- The length of the line segment from the origin to the point a+bi is √a2+b2.
-
- Z = 0.92.
- Finally, the height x is found using the Z score formula with the known mean µ, standard deviation σ, and Z score Z = 0.92.
- Z = 0.92.
- Finally, the height x is found using the Z score formula with the known mean µ, standard deviation σ, and Z score Z = 0.92.
- Erik's height is in the 40th percentile, marked with a black line.
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- For instance, $z = f(x, y) = x^2 + xy + y^2$.
- To every point on this surface, there is an infinite number of tangent lines.
- Partial differentiation is the act of choosing one of these lines and finding its slope.
- By finding the derivative of the equation while assuming that y is a constant, the slope of f at the point $(x, y, z)$ is found to be:
- That is to say, the partial derivative of $z$ with respect to $x$ at $(1, 1, 3)is3$.
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- One-dimensional figures (such as lines) and two-dimensional shapes (such as squares) are assigned zero volume in three-dimensional space.
- It can also mean a triple integral within a region D in R3 of a function $f(x,y,z)$, and is usually written as:
- of the function $z = f(x, y) = 5calculatedintheregionD$ in the $xy$-plane, which is the base of the cuboid.