Calculus
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Boundless Calculus
Advanced Topics in Single-Variable Calculus and an Introduction to Multivariable Calculus
Multiple Integrals
Calculus Textbooks Boundless Calculus Advanced Topics in Single-Variable Calculus and an Introduction to Multivariable Calculus Multiple Integrals
Calculus Textbooks Boundless Calculus Advanced Topics in Single-Variable Calculus and an Introduction to Multivariable Calculus
Calculus Textbooks Boundless Calculus
Calculus Textbooks
Calculus
Concept Version 5
Created by Boundless

Applications of Multiple Integrals

Multiple integrals are used in many applications in physics and engineering.

Learning Objective

  • Apply multiple integrals to real world examples


Key Points

    • Given a set D⊆RnD \subseteq R^nD⊆R​n​​ and an integrable function fff over DDD, the average value of fff over its domain is given by f¯=1m(D)∫Df(x)dx\bar{f} = \frac{1}{m(D)} \int_D f(x)dx​f​¯​​=​m(D)​​1​​∫​D​​f(x)dx, where m(D)m(D)m(D) is the measure of DDD.
    • The gravitational potential associated with a mass distribution given by a mass measure dmdmdm on three-dimensional Euclidean space R3R^3R​3​​ is V(x)=−∫R3G∣x−r∣dm(r)V(\mathbf{x}) = -\int_{\mathbf{R}^3} \frac{G}{|\mathbf{x} - \mathbf{r}|}\,dm(\mathbf{r})V(x)=−∫​R​3​​​​​∣x−r∣​​G​​dm(r).
    • An electric field produced by a distribution of charges given by the volume charge density ρ(r⃗)\rho (\vec r)ρ(​r​⃗​​) is obtained by a triple integral of a vector function: E⃗=14πϵ0∭r⃗−r⃗′∥r⃗−r⃗′∥3ρ(r⃗′)d3r′\vec E = \frac {1}{4 \pi \epsilon_0} \iiint \frac {\vec r - \vec r'}{\| \vec r - \vec r' \|^3} \rho (\vec r')\, {d}^3 r'​E​⃗​​=​4πϵ​0​​​​1​​∭​∥​r​⃗​​−​r​⃗​​​′​​∥​3​​​​​r​⃗​​−​r​⃗​​​′​​​​ρ(​r​⃗​​​′​​)d​3​​r​′​​.

Terms

  • Maxwell's equations

    a set of partial differential equations that, together with the Lorentz force law, form the foundation of classical electrodynamics, classical optics, and electric circuits

  • moment of inertia

    a measure of a body's resistance to a change in its angular rotation velocity


Full Text

As is the case with one variable, one can use the multiple integral to find the average of a function over a given set. Given a set D⊆RnD \subseteq R^nD⊆R​n​​ and an integrable function fff over DDD, the average value of fff over its domain is given by:

 f¯=1m(D)∫Df(x)dx\displaystyle{\bar{f} = \frac{1}{m(D)} \int_D f(x)\, dx}​f​¯​​=​m(D)​​1​​∫​D​​f(x)dx

where m(D)m(D)m(D) is the measure of DDD. Additionally, multiple integrals are used in many applications in physics and engineering. The examples below also show some variations in the notation.

Example 1

In mechanics, the moment of inertia is calculated as the volume integral (triple integral) of the density weighed with the square of the distance from the axis: 

Iz=∭Vρr2dV\displaystyle{I_z = \iiint_V \rho r^2\, dV}I​z​​=∭​V​​ρr​2​​dV

Example 2

The gravitational potential associated with a mass distribution given by a mass measure dmdmdm on three-dimensional Euclidean space R3R^3R​3​​ is:

 V(x)=−∫R3G∣x−r∣dm(r)\displaystyle{V(\mathbf{x}) = -\int_{\mathbf{R}^3} \frac{G}{\left|\mathbf{x} - \mathbf{r}\right|}\,dm(\mathbf{r})}V(x)=−∫​R​3​​​​​∣x−r∣​​G​​dm(r)

If there is a continuous function ρ(x)\rho(x)ρ(x) representing the density of the distribution at xxx, so that dm(x)=ρ(x)d3xdm(x) = \rho (x)d^3xdm(x)=ρ(x)d​3​​x, where d3xd^3xd​3​​x is the Euclidean volume element, then the gravitational potential is:

V(x)=−∫R3G∣x−r∣ρ(r)d3r\displaystyle{V(\mathbf{x}) = -\int_{\mathbf{R}^3} \frac{G}{\left|\mathbf{x}-\mathbf{r}\right|}\,\rho(\mathbf{r})\,d^3\mathbf{r}}V(x)=−∫​R​3​​​​​∣x−r∣​​G​​ρ(r)d​3​​r

A Mass to be Integrated

Points x\mathbf{x}x and r\mathbf{r}r, with r\mathbf{r}r contained in the distributed mass (gray) and differential mass dm(r)dm(\mathbf{r})dm(r)  located at the point r\mathbf{r}r.

Example 3

In electromagnetism, Maxwell's equations can be written using multiple integrals to calculate the total magnetic and electric fields. In the following example, the electric field produced by a distribution of charges given by the volume charge density ρ(r⃗)\rho (\vec r)ρ(​r​⃗​​) is obtained by a triple integral of a vector function: 

E⃗=14πϵ0∭r⃗−r⃗′∥r⃗−r⃗′∥3ρ(r⃗′)d3r′\displaystyle{\vec E = \frac {1}{4 \pi \epsilon_0} \iiint \frac {\vec r - \vec r'}{\| \vec r - \vec r' \|^3} \rho (\vec r')\, {d}^3 r'}​E​⃗​​=​4πϵ​0​​​​1​​∭​∥​r​⃗​​−​r​⃗​​​′​​∥​3​​​​​r​⃗​​−​r​⃗​​​′​​​​ρ(​r​⃗​​​′​​)d​3​​r​′​​

This can also be written as an integral with respect to a signed measure representing the charge distribution.

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