Algebra
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Boundless Algebra
Introduction to Equations, Inequalities, and Graphing
Introduction to Equations
Algebra Textbooks Boundless Algebra Introduction to Equations, Inequalities, and Graphing Introduction to Equations
Algebra Textbooks Boundless Algebra Introduction to Equations, Inequalities, and Graphing
Algebra Textbooks Boundless Algebra
Algebra Textbooks
Algebra
Concept Version 10
Created by Boundless

Rational Equations

A rational equation sets two rational expressions equal to each other and involves unknown values that make the equation true.

Learning Objective

  • Solve rational equations by finding a common denominator


Key Points

    • When solving a rational equation, find a common denominator or use the cross-multiplication method.
    • If the denominators are the same in a rational equation, the numerators must also be the same. Therefore, use the following strategy: find a common denominator, set the numerators equal to each other, and then solve for the variable, if necessary.

Terms

  • rational expression

    A set of mathematical terms that can be expressed as the quotient of two polynomials.

  • numerator

    The number or expression written above the line in a fraction (e.g., the 1 in $1/2$).

  • denominator

    The number or expression written below the line in a fraction (e.g., the 2 in $1/2$).

  • cross-multiply

    To multiply the numerator of each side of an equation by the denominator of the other side.


Full Text

Solving a Rational Equation (Same Denominators) 

For an equation that involves two fractions or rational expressions, cross-multiplying is a helpful strategy for simplifying the equation or determining the value of a variable.

For example, start with the following equation:

$\dfrac {x}{8} = \dfrac {3}{8}$

Cross-multiplying yields: 

$\begin{aligned} 8x&=8\cdot 3 \\ 8x&=24 \end{aligned}$

Now solve for $x$, by dividing both sides of the equation by $8$:

$\begin{aligned} \dfrac{8x}{8}&=\dfrac{24}{8} \\ x&=3 \end{aligned}$

We could also use simple algebra. Start with the same equation:

$\dfrac {x}{8} = \dfrac {3}{8}$

Isolate the variable on the left by multiplying both sides by $8$:

$\left(\dfrac{8}{1} \right)\cdot \dfrac{x}{8}= \left(\dfrac{8}{1} \right) \cdot \dfrac{3}{8}$

The denominators on both sides cancel out, yielding:

$x=3$

You could also come to this conclusion through deductive reasoning. Notice that the rational expressions on both sides of the equal sign have the same denominator. If you have a rational equation where the denominators on either side of the equation are the same, then their respective numerators must also be the same value, even though they might be expressed in different terms. This suggests a strategy: Find a common denominator, set the numerators equal to each other, and solve for any unknowns.

Solving a Rational Equation (Different Denominators) 

Several real-life situations can be modeled using equations that set two fractions, or ratios, to be equal to each other—for example, finding unknown dimensions of certain shapes.

Two triangles are said to be "similar" if they have equal corresponding angles. This is the same as the triangles having equal side-length ratios.

Similar geometric shapes

Two geometrical objects are similar if they both have the same shape or if one has the same shape as the mirror image of the other. In this image, figures shown in the same color are similar.

The two triangles below are similar. If length $\overline{AC}$ is 10 inches, $\overline{EF}$ is 14 inches, and $\overline{AB}$ is 17 inches, what is the length of $\overline{EG}$?

Similar triangles

Corresponding angles in similar shapes are marked with the same symbol. For example, $\angle A$ (i.e., angle $A$) corresponds to $\angle E$, and they are equal.

Let's start by writing a rational equation:

$\dfrac{\overline{AC}}{\overline{EF}}=\dfrac{\overline{AB}}{\overline{EG}}$ 

Now let's plug in the actual numbers:

$\dfrac{10}{14}=\dfrac{17}{x}$

Now cross-multiply:

$\begin{aligned} \dfrac{10}{14}\cdot (x) \cdot (14)&=\dfrac{17}{x} \cdot (x) \cdot (14) \\ 10\cdot x&=14\cdot 17 \\ 10x&=238 \end{aligned}$

Finally, divide both sides of the equation by 10:

$x=23.8 $ inches.

Therefore, $\overline{EG}$ is 23.8 inches long.

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